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Proof step 1 from proof inj-put (conclusion)

⊦ ¬ a ∈ st ∧ ¬ a ∈ st0 → (st[a, d] = st0[a, d] ↔ st = st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
st[a, d] = st0[a, d] ⊦ st = st0, a ∈ st0, a ∈ st

Rule argument

Additional information