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Proof step 4 from proof ins3 (previous step)

⊦ ∀ a0. (a0 ∈ st[a, d1][b, d0][a, d] ↔ a0 ∈ st[b, d0][a, d]) ∧ st[a, d1][b, d0][a, d][a0] = st[b, d0][a, d][a0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information