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Proof step 4 from proof k-Del-rec2 (previous step)

⊦ ∀ a0. (a0 ∈ st[a, d] -- b ↔ a0 ∈ (st -- b)[a, d]) ∧ (st[a, d] -- b)[a0] = (st -- b)[a, d][a0], a = b, a ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information