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Proof step 2 from proof rem-eq (previous step)

st -- a = st, a ∈ st ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ st1 = st2 ↔ (∀ a. (a ∈ st1 ↔ a ∈ st2) ∧ st1[a] = st2[a])
Proof step 4:
∀ a0. (a0 ∈ st -- a ↔ a0 ∈ st) ∧ (st -- a)[a0] = st[a0], a ∈ st ⊦

Rule argument

spec: inst: name: Extension seq: ⊦ st1 = st2 ↔ (∀ a. (a ∈ st1 ↔ a ∈ st2) ∧ st1[a] = st2[a]) subst: [st2, st1] → [st, st -- a] flags: rewrite, current

Additional information

Used terms: st, st -- a