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Proof step 4 from proof size-in (previous step)

st = (st -- a)[a, st[a]] ⊦ # st[a, d] = # st

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 5:
a ∈ st, st = (st -- a)[a, st[a]] ⊦ # st[a, d] = # st
Proof step 8:
st = (st -- a)[a, st[a]] ⊦ a ∈ st, # st[a, d] = # st

Rule argument

fma: a ∈ st

Additional information

Used formulas: a ∈ st