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Proof step 9 from proof size-in (previous step)

st = (st -- a)[a, st[a]] ⊦ a ∈ st

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: In-insert: ⊦ a ∈ st[b, d] ↔ a = b ∨ a ∈ st;