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Proof step 1 from proof size (conclusion)

⊦ a ∈ st → #(st -- a) = (# st)-1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
a ∈ st ⊦ #(st -- a) = # st - 1

Rule argument

Additional information

Used simplifier rules: pred-03: ⊦ n -1 = n - 1; from specification nat