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Proof step 2 from proof subset-delete-02 (previous step)

st ⊆ st0 ⊦ st -- a ⊆ st0

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: subset-delete-01 seq: ⊦ st ⊆ st0 → st -- a ⊆ st0 subst: [st, st0, a] → [st, st0, a] flags: current, []

Additional information

Used terms: st, st0, a