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Proof step 3 from proof subset-size (previous step)

# st0 < # st1[a, d], st1[a, d] ⊆ st0, ∀ st0. # st0 < # st1 → ¬ st1 ⊆ st0 ⊦ st1[a, d] = ∅

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 4:
a ∈ st1, # st0 < # st1[a, d], st1[a, d] ⊆ st0, ∀ st0. # st0 < # st1 → ¬ st1 ⊆ st0 ⊦ st1[a, d] = ∅
Proof step 17:
# st0 < # st1[a, d], st1[a, d] ⊆ st0, ∀ st0. # st0 < # st1 → ¬ st1 ⊆ st0 ⊦ a ∈ st1, st1[a, d] = ∅

Rule argument

fma: a ∈ st1

Additional information

Used formulas: a ∈ st1