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Proof step 3 from proof append-empty-01 (previous step)

⌜x⌝ + σ1 = [] ⊦ ⌜x⌝ = [] ∧ σ1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⌜x⌝ + σ1 = [] ⊦ x = [] ∧ σ1 = []

Rule argument

Additional information

Used simplifier rules: fin-empty: ⊦ ⌜x⌝ = [] ↔ x = [];