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Proof step 6 from proof append-from-le-01 (previous step)

m0 ≤ # x0, ∀ x0, a, σ. m0 ≤ # x0 + 1 ∧ (∀ m, σ. m ≤ # x0 → ⌜x0⌝ + σ from m = ⌜x0 from m⌝ + σ) → (⌜a '⌝ + ⌜x0⌝ ) + σ from m0 = ⌜a ' + x0 from m0⌝ + σ, ∀ m, σ. m ≤ # x0 → ⌜x0⌝ + σ from m = ⌜x0 from m⌝ + σ ⊦ ⌜x0⌝ + σ from m0 = ⌜x0 from m0⌝ + σ

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m0, σ

Additional information

Used terms: m0, σ