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Proof step 1 from proof append-split (conclusion)
⊦ finp(σ) ∧ # σ = # σ1 → (σ + σ0 = σ1 + σ2 ↔ σ = σ1 ∧ σ0 = σ2)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
# σ = # σ1, σ + σ0 = σ1 + σ2, finp(σ) ⊦ σ = σ1 ∧ σ0 = σ2
Rule argument
Additional information