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Proof step 6 from proof append-to-gr (previous step)

∀ y, n0. x0 + y to n0 + # x0 = x0 + (y to n0) ∨ n0 + # x0 = 0 ∨ n0 = 0 ⊦ n0 = 0, x0 + y to n0 + # x0 = x0 + (y to n0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: y, n0

Additional information

Used simplifier rules: z-01: ⊦ m + n = 0 ↔ m = 0 ∧ n = 0; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: y, n0