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Proof step 1 from proof cons-eq (conclusion)

⊦ ⌜a '⌝ + σ = ⌜a0 '⌝ + σ0 ↔ a = a0 ∧ σ = σ0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⌜a '⌝ + σ = ⌜a0 '⌝ + σ0 ⊦ a = a0 ∧ σ = σ0

Rule argument

Additional information