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Proof step 13 from proof cons-eq (previous step)

(λ n. (n = 0 ⊃ a0;nf(n - 1))) = (λ n. (n = 0 ⊃ a0;nf0(n - 1))) ⊦ nf = nf0

User applied rule expand right

And obtained the following new goals

Proof step 14:
(λ n. (n = 0 ⊃ a0;nf(n - 1))) = (λ n. (n = 0 ⊃ a0;nf0(n - 1))) ⊦ nf(n) = nf0(n)

Rule argument

pos: right 1

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