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Proof step 2 from proof elim-fromto-fin (
previous step
)
⊦ ¬ # σ < ⌜n⌝ → (σ0 = σ to n ∧ σ1 = σ from n ↔ σ = σ0 + σ1 ∧ # σ0 = ⌜n⌝ )
Lemma
elim-fromto