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Proof step 4 from proof eq-stream-to-list-2-1 (
previous step
)
⌜x + y⌝ = ⌜z⌝ ⊦ x + y = z
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 5
:
⊦ ⌜x⌝ = ⌜x0⌝ ↔ x = x0
Rule argument
spec: stream-basic inst: name: inj-02 seq: ⊦ ⌜x⌝ = ⌜x0⌝ ↔ x = x0 subst: [x0, x] → [z, x + y] flags: rewrite
Additional information
Used terms: z, x + y