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Proof step 1 from proof expand-cons (conclusion)

⊦ σ ≠ [] → (∃ a, σ0. σ = ⌜a '⌝ + σ0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ σ = [], ∃ a, σ0. σ = ⌜a '⌝ + σ0

Rule argument

Additional information