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Proof step 11 from proof expand-cons (previous step)

⊦ ⌜nf⌝ = ⌜λ n. (n = 0 ⊃ nf(0);nf(n -1 + 1))⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ nf(n) = (n = 0 ⊃ nf(0);nf((n - 1) + 1))

Rule argument

Additional information

Used simplifier rules: inj-01: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; from specification stream-basic%pred-03: ⊦ n -1 = n - 1; from specification nat