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Proof step 14 from proof expand-cons (
previous step
)
⊦ nf(n) = nf((n - 1) + 1), n = 0
Heuristic elimination applied rule insert elim lemma
And closed the goal!
Rule argument
spec: nat inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n, m] flags:
Additional information
Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n, m