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Proof step 4 from proof expand-cons (previous step)

⊦ x = [], ∃ a, σ0. ⌜x⌝ = ⌜a '⌝ + σ0

User applied rule structural induction

And obtained the following new goals

Proof step 5:
x0 = [] ∨ (∃ a, σ0. ⌜x0⌝ = ⌜a '⌝ + σ0) ⊦ a + x0 = [], ∃ a0, σ0. ⌜a + x0⌝ = ⌜a0 '⌝ + σ0

Rule argument

indvar: x

Additional information

Used simplifier rules: list freely generated by [], +;;