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Proof step 4 from proof extensionality-to (previous step)

# σ0 = # σ1, ∀ n. ¬ # σ1 < ⌜n⌝ → σ0 to n = σ1 to n ⊦ # σ0 = # σ1 ∧ (∀ n. ⌜n⌝ < # σ0 → σ0[n] = σ1[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information