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Proof step 28 from proof from-append-add (previous step)

nf0(n0 + n1 + n) = ((σ to n) + ⌜nf⌝ )[n0 + n1 + n] ⊦ nf0(n0 + n1 + n) = nf(n0 + n1), # σ < ⌜n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information