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Proof step 1 from proof from-append-toinffrom (conclusion)

⊦ ¬ # σ < ⌜n⌝ + n∞1 → (σ to n) + ((σ from n) to∞ n∞1) = σ to∞ ⌜n⌝ + n∞1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (σ to n) + ((σ from n) to∞ n∞1) = σ to∞ ⌜n⌝ + n∞1, # σ < ⌜n⌝ + n∞1

Rule argument

Additional information