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Proof step 1 from proof from-cons-one-fin (conclusion)

⊦ a ' + x from 1 = x

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ a ' + x from n + 1 = x from n

Rule argument

spec: inst: name: from-succ-cons-l-lem seq: ⊦ a ' + x from n + 1 = x from n subst: [a, x, n] → [a, x, 0] flags: current, []

Additional information

Used simplifier rules: from-zero-l: ⊦ x from 0 = x;%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: a, x, 0