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Proof step 1 from proof from-from-inf (conclusion)

⊦ nf from m from n = nf from m + n

User applied rule expand right

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: get-from-inf: ⊦ ((nf from n))(m) = nf(m + n);%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2