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Proof step 10 from proof from-from (
previous step
)
⊦ nf from m from n = nf from m + n
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 11
:
⊦ nf from n = (λ m. nf(n + m))
Proof step 12
:
⊦ (λ m0. nf(m + m0)) from n = nf from m + n
Rule argument
spec: stream inst: name: from-nf seq: ⊦ nf from n = (λ m. nf(n + m)) subst: [n, nf] → [m, nf] flags: rewrite, current
Additional information
Used terms: m, nf