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Proof step 1 from proof from-infto-exchange (conclusion)

⊦ ¬ # σ < ⌜m⌝ + n∞ → (σ to∞ ⌜m⌝ + n∞) from m = (σ from m) to∞ n∞

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (σ to∞ ⌜m⌝ + n∞) from m = (σ from m) to∞ n∞, # σ < ⌜m⌝ + n∞

Rule argument

Additional information