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Proof step 3 from proof from-succ-cons-l-lem (
previous step
)
⊦ a + x from n + 1 = x from n
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ a + x from n + 1 = x from n
Rule argument
spec: stream inst: name: from-succ-cons-l seq: ⊦ a + x from n + 1 = x from n subst: [n, x, a] → [n, x, a] flags: rewrite, current
Additional information
Used terms: n, x, a