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Proof step 12 from proof from-succ (previous step)

⌜n⌝ < # ⌜nf⌝ ⊦ ⌜nf⌝ from n = ⌜⌜nf⌝ [n] '⌝ + (⌜nf⌝ from n + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
⊦ ⌜nf from n⌝ = ⌜nf(n) '⌝ + ⌜nf from n + 1⌝

Rule argument

Additional information

Used simplifier rules: from-inf: ⊦ ⌜nf⌝ from n = ⌜nf from n⌝ ;%sel-inf: ⊦ ⌜nf⌝ [n] = nf(n);%size-inf: ⊦ # ⌜nf⌝ = ∞;%less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf