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Proof step 15 from proof from-succ (previous step)

⊦ ⌜nf from n⌝ = ⌜nf(n) '⌝ + ⌜λ m. nf((n + 1) + m)⌝

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ ⌜a '⌝ + ⌜nf⌝ = ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝
Proof step 17:
⊦ ⌜nf from n⌝ = ⌜λ n0. (n0 = 0 ⊃ nf(n);nf((n + 1) + n0 -1))⌝

Rule argument

spec: stream inst: name: one-inf seq: ⊦ ⌜a '⌝ + ⌜nf⌝ = ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝ subst: [nf, a] → [λ m. nf((n + 1) + m), nf(n)] flags: rewrite, current

Additional information

Used terms: λ m. nf((n + 1) + m), nf(n)