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Proof step 5 from proof get-append-notls (previous step)

m = n0 + # x, # x ≤ m ⊦ (⌜x⌝ + σ1)[m] = σ1[n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ (⌜x⌝ + σ1)[n0 + # x] = σ1[n0]

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%lep: ⊦ m ≤ m + n; from specification nat