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Proof step 7 from proof get-append-notls (previous step)

⊦ (⌜x⌝ + ⌜nf⌝ )[n0 + # x] = ⌜nf⌝ [n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
⊦ (⌜x⌝ + ⌜nf⌝ )[n0 + # x] = nf(n0)

Rule argument

Additional information

Used simplifier rules: sel-inf: ⊦ ⌜nf⌝ [n] = nf(n);