[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 5 from proof get-from-01 (previous step)

∀ m0, x0, a. m1 + m0 ≤ # x0 ∧ (∀ m, m0. m + m0 < # x0 → (x0 from m)[m0] = x0[m + m0] ∨ x0 = []) → (a ' + x0 from m1)[m0] = (a ' + x0)[m1 + m0], m1 +1 + m0 ≤ # x0, ∀ m, m0. m + m0 < # x0 → (x0 from m)[m0] = x0[m + m0] ∨ x0 = [] ⊦ (a ' + x0 from m1 +1)[m0] = (a ' + x0)[m1 +1 + m0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
m1 + m0 < # x0, ∀ m0, x0, a. m1 + m0 ≤ # x0 ∧ (∀ m, m0. m + m0 < # x0 → (x0 from m)[m0] = x0[m + m0] ∨ x0 = []) → (a ' + x0 from m1)[m0] = (a ' + x0)[m1 + m0], ∀ m, m2. m + m2 < # x0 → (x0 from m)[m2] = x0[m + m2] ⊦ (x0 from m1)[m0] = x0[m1 + m0], x0 = []

Rule argument

Additional information

Used simplifier rules: from-succ-cons-l-lem: ⊦ a ' + x from n + 1 = x from n;%l: ⊦ # x = 0 ↔ x = []; from specification list-data%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%succ-01: ⊦ m + 1 ≤ n ↔ m < n; from specification nat%get-succ: ⊦ (a ' + x)[n + 1] = x[n]; from specification list-del%a: ⊦ (x + y) + z = x + y + z; from specification list%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%succ: ⊦ m +1 = m + 1; from specification nat-basic2