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Proof step 11 from proof get-infto (previous step)

m0 < n0, ∀ m, nf. m < n0 → (nf to n0)[m] = nf(m) ⊦ ((λ n. nf(n + 1)) to n0)[m0] = nf(m0 + 1), n0 = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: m0, λ n. nf(n + 1)

Additional information

Used terms: m0, λ n. nf(n + 1)