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Proof step 1 from proof inf-not-toinf-exceptinf (conclusion)

⊦ ⌜nf⌝ = σ to∞ n∞ ↔ ¬ ¬(n∞ = ∞ ∧ ⌜nf⌝ = σ)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⌜nf⌝ = σ to∞ n∞ ⊦ n∞ = ∞ ∧ ⌜nf⌝ = σ

Rule argument

Additional information

Used simplifier rules: toinf-inf: ⊦ σ to∞ ∞ = σ;%inj-01: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; from specification stream-basic