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Proof step 4 from proof intrace-expand (previous step)

⊦ nf(n) = (n = 0 ⊃ nf(0);nf((n - 1) + 1))

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 5:
n ≠ 0 ⊦ nf(n) = nf((n - 1) + 1)

Rule argument

pos: right 1

Additional information