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Proof step 6 from proof leq-append-both (
previous step
)
∃ σ. σ1 + σ = σ2 ⊦ ∃ σ. σ1 + σ = σ2
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
⊦ ∃ σ0. σ1 + σ0 = σ1 + σ
Rule argument
Additional information