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Proof step 5 from proof leq-prefix (previous step)

⊦ σ = [], ∃ n. ⌜n⌝ < ⌜# x⌝ + # σ ∧ ⌜x⌝ + σ to n = ⌜x⌝

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: # x

Additional information

Used simplifier rules: size-empty-equiv: ⊦ # σ = ⌜0⌝ ↔ σ = [];%append-to-size-01: ⊦ ⌜x⌝ + σ to # x = ⌜x⌝ ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;%add-less-fin-01: ⊦ ⌜n⌝ < n∞ + ⌜n⌝ ↔ n∞ ≠ ⌜0⌝ ; from specification nat-inf%add-assoc: ⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2; from specification nat-inf%add-comm: ⊦ n∞1 + n∞2 = n∞2 + n∞1; from specification nat-inf%inj-02: ⊦ ⌜x⌝ = ⌜x0⌝ ↔ x = x0; from specification stream-basic Used terms: # x