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Proof step 1 from proof leq-symm (conclusion)

⊦ σ1 ≤ σ2 ∧ σ2 ≤ σ1 → σ1 = σ2

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: leq-symm-2: ⊦ σ1 ≤ σ2 → (σ2 ≤ σ1 ↔ σ1 = σ2);