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Proof step 1 from proof leq-trans (conclusion)
⊦ σ ≤ σ1 ∧ σ1 ≤ σ2 → σ ≤ σ2
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
σ ≤ σ1, σ1 ≤ σ2 ⊦ σ ≤ σ2
Rule argument
Additional information