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Proof step 4 from proof leq-trans (previous step)

σ ≤ σ1, σ1 ≤ σ2 ⊦ ∃ σ0. σ + σ0 = σ2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ σ1 ≤ σ2 ↔ (∃ σ. σ1 + σ = σ2)
Proof step 6:
∃ σ0. σ + σ0 = σ1, σ1 ≤ σ2 ⊦ ∃ σ0. σ + σ0 = σ2

Rule argument

spec: stream inst: name: prefix-def seq: ⊦ σ1 ≤ σ2 ↔ (∃ σ. σ1 + σ = σ2) subst: [σ2, σ1] → [σ1, σ] flags: rewrite, current

Additional information

Used terms: σ1, σ