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Proof step 1 from proof swap-from-to (conclusion)

⊦ ¬ # σ < ⌜m⌝ + ⌜n⌝ → (σ from m) to n = (σ to m + n) from m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ (σ from m) to n = (σ to m + n) from m, # σ < ⌜m⌝ + ⌜n⌝

Rule argument

Additional information