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Proof step 27 from proof swap-from-to (previous step)

¬ #(σ from m) < ⌜n⌝ ⊦ ⌜n⌝ = #((σ to m + n) from m), # σ < ⌜m⌝ + ⌜n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
⊦ ⌜n⌝ = #((σ to m + n) from m), # σ < ⌜m⌝ + ⌜n⌝ , #(σ from m) < ⌜n⌝

Rule argument

Additional information