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Proof step 1 from proof tl-inf-1 (conclusion)

⊦ tl(a + ⌜nf⌝ ) = ⌜nf⌝

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: stream inst: name: cons-inf seq: ⊦ a + ⌜nf⌝ = ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝ subst: [nf, a] → [nf, a] flags: rewrite, current

Additional information

Used simplifier rules: tl-inf: ⊦ tl(⌜nf⌝ ) = ⌜λ n. nf(n +1)⌝ ;%pred-03: ⊦ n -1 = n - 1; from specification nat%succ: ⊦ m +1 = m + 1; from specification nat-basic2%oz: ⊦ m + 1 ≠ 0; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%add-01: ⊦ n ≤ m → m + n0 - n = (m - n) + n0; from specification nat%add-base: ⊦ n + 0 = n; from specification nat-basic2%inj-01: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; from specification stream-basic Used terms: nf, a