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Proof step 1 from proof to-plus-from-fin-simp (conclusion)

⊦ ¬ # x < n → ((x to n) + (x from n) ≠ x ↔ false)

User applied rule insert elim lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ # x < n → (x0 = x to n ∧ x1 = x from n ↔ x = x0 + x1 ∧ # x0 = n)

Rule argument

spec: stream inst: name: elim-fromto-fin seq: ⊦ ¬ # x < n → (x0 = x to n ∧ x1 = x from n ↔ x = x0 + x1 ∧ # x0 = n) subst: [x, n, x0, x1] → [x, n, x0, x1] flags: rewrite, current

Additional information

Used terms: x, n, x0, x1