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Proof step 3 from proof to-plus-from-inf (previous step)

nf = (⌜x⌝ + ⌜nf0⌝ ).f ∧ # x = n ⊦ ⌜x⌝ + ⌜nf0⌝ = ⌜nf⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information