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Proof step 2 from proof to-plus-from-simp (
previous step
)
⊦ (σ to n) + (σ from n) = σ, # σ < ⌜n⌝
User applied rule insert elim lemma
And obtained the following new goals
Proof step 3
:
⊦ ¬ # σ < ⌜n⌝ → (σ0 = σ to n ∧ σ1 = σ from n ↔ σ = σ0 + σ1 ∧ # σ0 = ⌜n⌝ )
Rule argument
spec: stream inst: name: elim-fromto seq: ⊦ ¬ # σ < ⌜n⌝ → (σ0 = σ to n ∧ σ1 = σ from n ↔ σ = σ0 + σ1 ∧ # σ0 = ⌜n⌝ ) subst: [σ, n, σ0, σ1] → [σ, n, σ0, σ1] flags: rewrite, current
Additional information
Used terms: σ, n, σ0, σ1