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Proof step 1 from proof to-plus-from (conclusion)

⊦ ¬ # σ < ⌜n⌝ → (σ to n) + (σ from n) = σ

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: to-plus-from-simp: ¬ # σ < ⌜n⌝ ⊦ (σ to n) + (σ from n) ≠ σ ↔ false;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;