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Proof step 21 from proof to-to-leq-inf (previous step)

∀ m, nf. m ≤ n0 → (nf to n0) to m = nf to m ⊦ (nf to n0) to n0 = nf to n0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: n0, nf

Additional information

Used simplifier rules: ler: ⊦ m ≤ m; from specification nat Used terms: n0, nf